SOLUTION: can you tell me if i did this problem right? solve each equation 4x^2 + 8x = 0 x(4x + 8) = 0 x(2x + 2) (4x + 4) =0 x=2 x=-4

Algebra ->  Square-cubic-other-roots -> SOLUTION: can you tell me if i did this problem right? solve each equation 4x^2 + 8x = 0 x(4x + 8) = 0 x(2x + 2) (4x + 4) =0 x=2 x=-4       Log On


   

Question 118221: can you tell me if i did this problem right?
solve each equation
4x^2 + 8x = 0
x(4x + 8) = 0
x(2x + 2) (4x + 4) =0
x=2 x=-4

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2%2B8x=0 Start with the given equation

4x%28x%2B2%29=0 Factor the left side.


Now set each factor equal to zero:
4x=0 or x%2B2=0

x=0 or x=-2 Now solve for x in each case


So our answer is
x=0 or x=-2


Notice if we graph y=4x%5E2%2B8x we can see that the roots are x=0 and x=-2 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+4x%5E2%2B8x%29+