SOLUTION: 7sqrt7x+5sqrt7x The instruction says to "simplify". Can someone show me how to do this one? Thank you!

Algebra ->  Square-cubic-other-roots -> SOLUTION: 7sqrt7x+5sqrt7x The instruction says to "simplify". Can someone show me how to do this one? Thank you!      Log On


   

Question 110218: 7sqrt7x+5sqrt7x
The instruction says to "simplify". Can someone show me how to do this one?
Thank you!
Found 3 solutions by stanbon, jim_thompson5910, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
7sqrt7x+5sqrt7x
The instruction says to "simplify".
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Your problem is like 7 cars + 5 cars
The sum is 12 cars
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Your Problem:
7(sqrt7x) + 5(sqrt7x) = 12sqrt7x
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Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If we let y=sqrt%287x%29 we get

7y%2B5y

Now combine like terms

7y%2B5y=%287%2B5%29y=12y


Now plug y=sqrt%287x%29 back in to get

12y=12%2Asqrt%287x%29

So in other words, 7%2Asqrt%287x%29%2B5%2Asqrt%287x%29=12%2Asqrt%287x%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
7%2Asqrt%287x%29+%2B+5%2Asqrt%287x%29
If I'm reading the expression right, the common factor in the terms
is sqrt%287x%29, so I'll factor it out
sqrt%287x%29%287+%2B+5%29
12%2Asqrt%287x%29 answer