SOLUTION: find all zeroes. f(x)=25x^8-26x^4+1
Algebra
->
Square-cubic-other-roots
-> SOLUTION: find all zeroes. f(x)=25x^8-26x^4+1
Log On
Algebra: Square root, cubic root, N-th root
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Square-cubic-other-roots
Question 1091092
:
find all zeroes.
f(x)=25x^8-26x^4+1
Answer by
CubeyThePenguin(3113)
(
Show Source
):
You can
put this solution on YOUR website!
Let x^4 = y.
f(x) = 25y^2 - 26y + 1
= (25y - 1)(y - 1)
x^4 = 1 ---> x = 1, -1,
,
x^4 = 1/25 ---> x = +sqrt(5)/5, -sqrt(5)/5,
,
Usually you will only need the real solutions, but I have added the complex solutions just in case.