SOLUTION: For which values of x is the radical expression a real​ number? {{{sqrt(-10-2x)}}} I know how to solve the inequality part once I have everything, but what I'm not unders

Algebra ->  Square-cubic-other-roots -> SOLUTION: For which values of x is the radical expression a real​ number? {{{sqrt(-10-2x)}}} I know how to solve the inequality part once I have everything, but what I'm not unders      Log On


   

Question 1032057: For which values of x is the radical expression a real​ number?
sqrt%28-10-2x%29
I know how to solve the inequality part once I have everything, but what I'm not understanding is how to decide which sign to use (like ≥).
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The entire expression inside the square root function must take only non-negative values.

-10-2x%3E=0.
Do you know what to do from here?


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