SOLUTION: How do you graph k(x)=x^2-6 with 5 points? & How do you graph h(x)= square root x-2 with 5 points?

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Question 1020491: How do you graph k(x)=x^2-6 with 5 points?
&
How do you graph h(x)= square root x-2 with 5 points?
Found 2 solutions by josgarithmetic, Fombitz:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
Pick any five x values and evaluate k for each of them and graph the points. You will have a parabola opening upward, with vertex moved to (0,-6).

graph%28300%2C300%2C-7%2C7%2C-7%2C7%2Cx%5E2-6%29
That is your first equation or function, k(x); not the second one or h(x).

h(x) is a top branch of a parabola, because square root function based. Similar idea but h%28x%29=sqrt%28x-2%29. The vertex will be (2,0).

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Pick 5 x values.
Generate 5 y values.
I'll do 2, you do the rest.
x=0
y=0%5E2-6=-6
(0,-6)
.
.
x=1
y=1%5E2-6
y=1-6
y=-5
(1,-5)
Do the same for the remaining three points.
.
.
.
Do the same for this function.
Keep in mind, the value under the square root must be positive!