SOLUTION: I need help.
simplify. do not evaluate exponential numbers.
a) (3^-2/4^3)^-1 * (3/4)
b) 3^-1*2^2*3^3 / 2^2*3^2 + (3/2)^0
c) (7^4*6^3*7^-5/7^-3*6^0)^2 / (6^5*7^-2/6^-4
Algebra ->
Square-cubic-other-roots
-> SOLUTION: I need help.
simplify. do not evaluate exponential numbers.
a) (3^-2/4^3)^-1 * (3/4)
b) 3^-1*2^2*3^3 / 2^2*3^2 + (3/2)^0
c) (7^4*6^3*7^-5/7^-3*6^0)^2 / (6^5*7^-2/6^-4
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Question 1017156: I need help.
simplify. do not evaluate exponential numbers.
a) (3^-2/4^3)^-1 * (3/4)
b) 3^-1*2^2*3^3 / 2^2*3^2 + (3/2)^0
c) (7^4*6^3*7^-5/7^-3*6^0)^2 / (6^5*7^-2/6^-4)^3 Answer by MathTherapy(10801) (Show Source):
I need help.
simplify. do not evaluate exponential numbers.
a) (3^-2/4^3)^-1 * (3/4)
b) 3^-1*2^2*3^3 / 2^2*3^2 + (3/2)^0
c) (7^4*6^3*7^-5/7^-3*6^0)^2 / (6^5*7^-2/6^-4)^3
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Responding to c), the SEEMINGLY most complex of the 3.
c) = = = = = = = = , or
