Questions on Algebra: Square root, cubic root, N-th root answered by real tutors!

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Question 1073123: A school buys 200 calculators at a special price. x of them were scientific calculators at R89 a piece and
the rest were financial calculators at R599 a piece. An expression, in terms of x, for the total number of
financial calculators bought is ...

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Question 277236: What is the square root of 9y to the 6th power?
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Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x
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Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x
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Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x
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Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x
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Question 520404: square root of 12 divided by square root of 6
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Question 97658: I need help completing the square for this problem.
16x^2-16x-5=0

So far I have tried this:
16x^2-16x+[1/2(-16)]=5+[1/2(-16)]
16x^2-16x+64=5+64
16(x^2-x+4)=69
16(????????????

I'm lost from this point on. I tried factoring but it's not working for me. I hope you can help me.
Thank you very much
Solve a Quadratic Equation by completing the square.
I was not sure what would be an acceptable answer for your teacher so I worked it all the way out. This problem is a Quadratic Equation. Here is your solution.

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Question 265331: the squareroot of -12 + 2x = the squareroot of 3x+23
please provide step by step

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Question 969387: sir what is the root of 5+2*root 6

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Question 969387: sir what is the root of 5+2*root 6

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Question 988996: √(7-4√3) + √(7+4√3)
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Question 988996: √(7-4√3) + √(7+4√3)
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Question 967135: 2 to the n power multiplied by 2' all over 2 to -5 power equals 2 squared, solve for n
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Question 973570: Hi,
Well I've run into a problem that I can't really do.
The question is to rationalise 1/(cube root 2 - 1). The answer is cube root 2 + cube root 4 + 1. I know how to rationalise 1/cube root 2 but I'm not sure how to do this one. What I got is:
1/cube root 2-1=1/cube root 2-1 * (cube root 2^2 + 1)/(cube root 2^2 + 1)
And I've so on and so forth, but I didn't get the right answer. I got cube root 4 + 1.
Thanks

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Question 973570: Hi,
Well I've run into a problem that I can't really do.
The question is to rationalise 1/(cube root 2 - 1). The answer is cube root 2 + cube root 4 + 1. I know how to rationalise 1/cube root 2 but I'm not sure how to do this one. What I got is:
1/cube root 2-1=1/cube root 2-1 * (cube root 2^2 + 1)/(cube root 2^2 + 1)
And I've so on and so forth, but I didn't get the right answer. I got cube root 4 + 1.
Thanks

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Question 973174: x^1/2 + y = 7
x + y^1/2 = 11
Find the value of x and y

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Question 1017156: I need help.
simplify. do not evaluate exponential numbers.
a) (3^-2/4^3)^-1 * (3/4)
b) 3^-1*2^2*3^3 / 2^2*3^2 + (3/2)^0
c) (7^4*6^3*7^-5/7^-3*6^0)^2 / (6^5*7^-2/6^-4)^3

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Question 1051380: simplify the expression and show check of work please if you can. x and y represent nonegative real numbers. I attempted to do this expression however I have two different answers. can someone please help
sqrt(25x^32 y^8 z^6)

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Question 991238: What is the equation to find the 21th number of the sequence: 4, 6, 10, 16, ...
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Question 1154852: Bobby just received an award for employee of the year and wants to frame the plaque in b) such a way as it creates a border of uniform width around the rectangular plaque. He only has enough material to create a total of 16 square inches in area for the border. If the plaque is 6 inches by 9 inches, how wide should the border be?
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Question 325791: sqrt(4x+5) = 2 + sqrt(2x-1)
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Question 99970: Please help. I have one last problem on my test due tonight. I know I am not giving you a lot of time but the person that usually helps me has ended up in the hospital and I am stuck on this last question.
Solve sqrt2x-1=sqrt4x-1 with another -1 outside the sqrt part.
Thanks if you have the time.

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Question 648428: please help me solve this equation:
sqrt ( 32 ) times(multiply) sqrt ( 6 )

i am trying to simplify this equation down to a number and a square root..
my last step i got
sqrt ( 8 ) (times) sqrt ( 4 ) (times) sqrt ( 6 )
and i dont know what to do next...
thank you in advance for your help!

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Question 51682: I have the answer in the back of the book. Still having trouble getting there.
4^2/3 * 6^2/3 * 9^2/3
Have tried squaring 4 and then taking the cubed root but don't get good numbers.
The book says answer is 36?????

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Question 252005: Can you please help me with this equation: 2- sqrt 7 / sqrt 3 - sqrt 2
the answer I have is (2- sqrt 7)(sqrt 3 + sqrt 2 / 5 but i don't think it is right.

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Question 96313: 3+sqrt%28+11+%29+ * 2+sqrt%28+11+%29+
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Question 96313: 3+sqrt%28+11+%29+ * 2+sqrt%28+11+%29+
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Question 1164689: c) The equation of a curve is y = squrt of 5x + y
i. Calculate the gradient of the curve at the point where x = 1
ii. A point with coordinates (x,y) moves along the curve in such a way that
the rate of increase of x has the constant value 0.03 units per second. Find
the rate of increase of y ath the instant when x = 1.
iii. Find the area enclosed by the curve, the x - axis, the y - axis and the line
y = 1.

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Question 485853: What is 9 divided by the cubed root of 3?
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Question 308197: What is the cubed root of 4x squared divided by the cubed root of 16?
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Question 457475: How do I solve and algebra problem with a squared variable? 25=16-Tsquared

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Question 262842: Simplify:
(sqrt(50) - 2sqrt(5))(5sqrt(2) + sqrt(20))

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Question 983405: Cuberoot of 32.768 with steps.
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Question 236908: I am reveiwing algebra on my own in my old age. I am stumped on a problem. I need to find the 6th root of 225. I have broken the equation down into the square and the 3rd root, but cannot find the book answer which is the cube root of 15. Can you help? I am over half way through the book and do not move on until I have solved all of the odd numbered problems and checked my answers against the book answers.
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Question 100682: Good Evening Tutor,
I have two questions I was wondering if you could tell me if I got them correct?
1.) Evaluate if possible: cubed(3) sqrt of -8/27 I got - 1/6 is this correct?
2.) simplify by combining like terms. sqrt of 63 - 2 sqrt of 28 + 5 sqrt of 7.
I got 7 sqrt of 7 I think this is wrong but I am not sure where I am getting messed up I keep getting the same answer.
Any help is appreciated. Thank you.

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Question 1117168: solve Sqrt {2+sqrt {3}}
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Question 717026: one number is twice the another number and their product is 2048 . what are the two number
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Question 202363: if (125/27)^x = the cubic root of 0.6 then the value of x is _______


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Question 202363: if (125/27)^x = the cubic root of 0.6 then the value of x is _______


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Question 243853: cube root of 27w to the 12th power over 100
cube%28+27w%5E12%2F100+%29+
Explanation:
I am a volunteer math tutor. My student disagrees with the answer I came up with, so I am writing to you for any help in justifying her answer or my answer as "more correct". Here's the problem: Show your work in solving this cube root problem.
The heart of the question is my student's answer vs. my answer. Which one is more correct?
Student:
cube( (3 x 3 x 3) w^(4 x 3)/(75 + 25) )
3w4/(5 x 5 x 5) + cube( 25 )
3w4/5 + cube ( 25 ) <<< student's answer
Tutor:
cube( (3 x 3 x 3) w^(4 x 3)/(75 + 17 + 8) )
3w4/(5 x 5 x 5) + cube( 17 ) + (2 x 2 x 2)
3w4/5 + cube ( 17 ) + 2
3w4/7 + cube (17) <<< tutor's answer
Which answer will the teacher of my student consider as "correct" ?
3w4/5 + cube ( 25 ) OR 3w4/7 + cube (17)
Thank you. Rob Miller

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Question 558894: use the square root property to solve the equation

(1) (x+1)^2=9

(2) x^2=121

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Question 1181912: Al-khwarizmi solved all quadratic equations by reducing them to one of six standard forms, which were then easily solvable. He described the standard forms in terms of “squares”,”roots”, and “numbers”. Here are al-khwarizmis six standard forms.
1. Squares equal to roots(example:ax^2=bx)
2. Squares equal to numbers(example:ax^2=c)
3.roots equal to numbers(example:bx=c)
4.squares and roots equal to numbers (example:ax^2+bx=c)
5. Squares and numbers equal to roots (example: ax^2+c=bx)
6.roots and numbers equal to tot squares(example:ax^2=bx+c)
Which method would you use to solve each of the six forms? Why would you use that method?
Write a quadratic equation that can be reduced to one of al-khwarizmis six forms.

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Question 1209713: Let a and b be integer such that (2 + sqrt(5))(137) = a + b sqrt(5). Compute a^2 - 5b^2.
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Question 1183944: Al-Khwarizmi solved all quadratic equations by reducing them to one of six standard forms, which were then easily solvable. He described the standard forms in terms of "squares," "roots," and "numbers." Here are al-Khwarizmi's six standard forms:
squares equal to roots (Example: ax2= bx
a x squared equals space b x)
squares equal to numbers (Example: ax2= c
a x squared equals space c)
roots equal to numbers (Example: bx=c
b x equals c)
squares and roots equal to numbers (Example: ax2+bx=c
a x squared plus b x equals c)
squares and numbers equal to roots (Example: ax2+c=bx
a x squared plus c equals b x)
roots and numbers equal tot squares (Example: ax2=bx+c
a x squared equals b x plus c)
Activity Instructions
• Which method would you use to solve each of the six forms? Why would you use that method?
• Write a quadratic equation that can be reduced to one of al-Khwarizmi's six forms.

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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425