SOLUTION: 1) 13+(-3)^2+4(-3)+1-[-10-(-6)] ----------- ----------- ----------- --- {[4+5]/[4^2-3^2(4-3)-8]}+12
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-> SOLUTION: 1) 13+(-3)^2+4(-3)+1-[-10-(-6)] ----------- ----------- ----------- --- {[4+5]/[4^2-3^2(4-3)-8]}+12
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Question 951696
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1) 13+(-3)^2+4(-3)+1-[-10-(-6)]
---------------------------------------
{[4+5]/[4^2-3^2(4-3)-8]}+12
Answer by
CubeyThePenguin(3113)
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numerator: 13 + (-3)^2 + 4(-3) + 1 - (-10 - (-6))
= 13 + 9 - 12 + 1 + 4
= 15
denominator: [(4 + 5)/(4^2 - 3^2(4 - 3) - 8)] + 12
= (9/(16 - 9 - 8)) + 12
= 9/(-1) + 12
= 3
fraction: 15/3 = 5