SOLUTION: f(x)=x^2+2x then what is the value of f(x-1) ?

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Question 761737: f(x)=x^2+2x then what is the value of f(x-1) ?
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=x^2+2x
f(x - 1) = (x - 1)^2 + 2(x - 1)
= x^2 - 2x + 1 + 2x - 2
= x^2 - 1
Hope this helps.
:-)