SOLUTION: I seem to be having issues with the equations with fractions in them. I'm getting frustrated because just when I think I have it down, I end up with the wrong answer. If you can
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Question 11621: I seem to be having issues with the equations with fractions in them. I'm getting frustrated because just when I think I have it down, I end up with the wrong answer. If you can please help me, here's a problem I am having issues with.
2/3{-3/8 + [(3/4)^3 / (-3/5)^2]}
If it helps I'll say what I am doing and maybe you can tell me what I am doing wrong. First I take 3/4^3 which is 27/64 divided by -3/5^2 which is 9/25...so at this point I have an eqation of 2/3{-3/8 + [27/64 / 9/25]} this is where I get confused...so if you have any idea what I'm doing...please help me...thanks a million ~V Found 2 solutions by CubeyThePenguin, MathTherapy:Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! 2/3{-3/8 + [(3/4)^3/(-3/5)^2)}
= 2/3{-3/8 + [(27/64) * (25/9)]}
= 2/3{-3/8 + 75/64}
= 2/3{51/64}
=
I seem to be having issues with the equations with fractions in them. I'm getting frustrated because just when I think
I have it down, I end up with the wrong answer. If you can please help me, here's a problem I am having issues with.
2/3{-3/8 + [(3/4)^3 / (-3/5)^2]}
If it helps I'll say what I am doing and maybe you can tell me what I am doing wrong. First I take 3/4^3 which is 27/64
divided by -3/5^2 which is 9/25...so at this point I have an eqation of 2/3{-3/8 + [27/64 / 9/25]} this is where
I get confused...so if you have any idea what I'm doing...please help me...thanks a million ~V
<==== You got up to HERE! ---- Applying KCF (Keep, Change, Flip) on , to make it =
