SOLUTION: The sum of three numbers in a.p is 12 and the sum of their squares is 66. what are the numbers

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Question 997811: The sum of three numbers in a.p is 12 and the sum of their squares is 66. what are the numbers
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
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Let x  be a middle number,  then the first one is  x-d  and the third one is  x+d,  where  d  is the common difference.

The sum of three is  12.  It means that

(x-d) + x + (x+d) = 12,     or

3x = 12,     x = 12%2F3 = 4.

The sum of squares is  66.  It means that

%284-d%29%5E2+%2B+4%5E2+%2B+%284%2Bd%29%5E2 = 66,     or

16+-+8d+%2B+d%5E2 + 16 + 16+%2B+8d+%2B+d%5E2 = 66,

48 + 2d%5E2 = 66,

2d%5E2 = 66-48,

2d%5E2 = 18,

d%5E2 = 18%2F2 = 9,   d = +/-3.

Thus our progression is   1, 4, 7   or   7, 4, 1.