SOLUTION: .Find k so that the numbers 2k+1, 3k+4, and 7k+6 form a geometric sequence

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Question 981788: .Find k so that the numbers 2k+1, 3k+4, and 7k+6 form a geometric
sequence
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
A geometric sequence forms when there is a common ratio r.

To find the common ratio r, divide a given term by the previous term

So if you picked the second term as the "given term", then...
r+=+%28second_term%29%2F%28first_term%29
r+=+%283k%2B4%29%2F%282k%2B1%29

If you picked the third term as the "given term", then...
r+=+%28third_term%29%2F%28second_term%29
r+=+%287k%2B6%29%2F%283k%2B4%29

The two r values are the same, so we can equate the expressions to get
%287k%2B6%29%2F%283k%2B4%29+=+%283k%2B4%29%2F%282k%2B1%29

Now solve the equation for k. I'll let you do this part.