SOLUTION: 1) If alfa,beta are real and alfa square,-beta square are the roots of the equation a2x2+x+(1-a2)=0,a>1,then beta square=_________ 2)If (1-p) is aroot of a qadratic equation x2+

Algebra ->  Sequences-and-series -> SOLUTION: 1) If alfa,beta are real and alfa square,-beta square are the roots of the equation a2x2+x+(1-a2)=0,a>1,then beta square=_________ 2)If (1-p) is aroot of a qadratic equation x2+      Log On


   



Question 981552: 1) If alfa,beta are real and alfa square,-beta square are the roots of the equation a2x2+x+(1-a2)=0,a>1,then beta square=_________
2)If (1-p) is aroot of a qadratic equation x2+px+(1-p)=0,then its roots are______

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
This response deals with your second question.
If 1-p is a root, then you must be asking what is the other root for x%5E2%2Bpx%2B%281-p%29=0.

More than one way to go, but,
x=%28-p%2B-+sqrt%28p%5E2-4%2A%281-p%29%29%29%2F2, using general formula for solution to a quadratic equation.

x=%28-p%2B-+sqrt%28p%5E2-4%2B4p%29%29%2F2

x=%28-p%2B-+sqrt%28p%5E2%2B4p-4%29%29%2F2----------these would be the roots!

You were expecting that 1-p is one of the roots. Check if it really is a root.
%281-p%29%5E2%2Bp%281-p%29%2B%281-p%29
1-2p%2Bp%5E2%2Bp-p%5E2%2B1-p
1%2B1-2p%2Bp-p%2Bp%5E2-p%5E2
2-2p=0------Not true, because this depends on the value of p.

Your question or description for your exercise 2 is faulty.