SOLUTION: My book says that the sum of the first 10 terms of the sequence {300,150,75,...} is {{{75(2^10-1)/2^7}}} Why is this? Using the formula {{{ A1(1-r^n)/(1-r) }}} I got {{{3

Algebra ->  Sequences-and-series -> SOLUTION: My book says that the sum of the first 10 terms of the sequence {300,150,75,...} is {{{75(2^10-1)/2^7}}} Why is this? Using the formula {{{ A1(1-r^n)/(1-r) }}} I got {{{3      Log On


   

Question 973330: My book says that the sum of the first 10 terms of the sequence {300,150,75,...} is 75%282%5E10-1%29%2F2%5E7
Why is this? Using the formula ++A1%281-r%5En%29%2F%281-r%29+ I got 300%281-%281%2F2%29%5E10%29%2F%281-1%2F2%29
Am I wrong? Or is my answer simply in a different form? If so, please explain how I can arrive at the answer similar to the one found in my book.
Much Thanks.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll show you how to transform your answer into the book's answer


300%281-%281%2F2%29%5E10%29%2F%281-1%2F2%29


300%281-%281%5E10%29%2F%282%5E10%29%29%2F%281-1%2F2%29


300%281-%281%29%2F%282%5E10%29%29%2F%281-1%2F2%29


300%281%2A%28%282%5E10%29%2F%282%5E10%29%29-%281%29%2F%282%5E10%29%29%2F%281-1%2F2%29


300%28%282%5E10%29%2F%282%5E10%29-%281%29%2F%282%5E10%29%29%2F%282%2F2-1%2F2%29


300%28%282%5E10-1%29%2F%282%5E10%29%29%2F%28%282-1%29%2F2%29


300%28%282%5E10-1%29%2F%282%5E10%29%29%2F%281%2F2%29


300%28%282%5E10-1%29%2F%282%5E10%29%29%2A%282%2F1%29


300%28%282%5E10-1%29%2F%282%5E10%29%29%2A%28%282%5E1%29%2F1%29


300%28%282%5E10-1%29%2F%282%5E9%29%29


75%2A4%28%282%5E10-1%29%2F%282%5E9%29%29


75%2A2%5E2%2A%28%282%5E10-1%29%2F%282%5E9%29%29


75%2A%28%282%5E10-1%29%2F%282%5E7%29%29


So that shows how your answer is equivalent to the book's answer. The book's answer is slightly simpler though.