SOLUTION: What are the next two numbers in this series 1,8,27,58

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Question 970169: What are the next two numbers in this series 1,8,27,58

Answer by MathLover1(20850) About Me  (Show Source):
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1,8,27,58
first find the pattern:
To find the pattern, I will list the numbers, and find the differences for each pair of numbers. That is, I will subtract the numbers in pairs (the first from the second, the second from the third, and so on), like this:
1.........8..........27..........58.....
.....7.........19.........31.... the "first differences", are not all the same value, I'll continue subtracting:
..........12.........12....=> the second differences are the same, so the polynomial for this sequence of values is a quadratic
Since the formula for the terms is a quadratic, then I know that it is of the form:
an%5E2+%2B+bn+%2B+c+ for some numbers a, b, and c
Now I have to find those numbers by plugging in some of the values from the sequence, and then solving the resulting system of equations.
if n=1 first term is 1
a%2A1%5E2+%2B+b%2A1+%2B+c=1+
a+%2B+b+%2B+c=1 ..........eq.1

if n=2 second term is 8
a%2A2%5E2+%2B+b%2A2+%2B+c=8+
4a+%2B+2b+%2B+c=8 ..........eq.2

if n=3 third term is 27
a%2A3%5E2+%2B+b%2A3+%2B+c=27
9a+%2B+3b+%2B+c=27 ..........eq.3
start with
4a+%2B+2b+%2B+c=8 ..........eq.2
a+%2B+b+%2B+c=1 ..........eq.1
--------------------------------subtract
3a+%2B+b=7 --------solve for b
b=7-3a.........................(1)
now use
9a+%2B+3b+%2B+c=27 ..........eq.3
4a+%2B+2b+%2B+c=8 ..........eq.2
--------------------------------subtract
5a%2Bb=19--------solve for b
b=19-5a.........................(2)
use (1) and (2) to find a
7-3a=19-5a
5a-3a=19-7
2a=12
highlight%28a=6%29
now find b
b=7-3a.........................(1)
b=7-3%2A6
b=7-18
highlight%28b=-11%29
go to eq.1 substitute a and b , and find c
a+%2B+b+%2B+c=1 ..........eq.1
6+-11+%2B+c=1+
-5+%2B+c=1+
c=1%2B5
highlight%28c=6%29
so, your polynomial,or nth term formula is:
a%5Bn%5D+=+6n%5E2-11n%2B6 .......(for all terms given)
now use formula to find the next two numbers in this series:
a%5B5%5D+=+6%2A5%5E2-11%2A5%2B6
a%5B5%5D+=+150-55%2B6
a%5B5%5D+=+101

a%5B6%5D+=+6%2A6%5E2-11%2A6%2B6
a%5B6%5D+=+216-66%2B6
a%5B6%5D+=+156

so, with these terms, your sequence is: 1,8,27,58,101,156