SOLUTION: Please help me solve this problem the sequence is as follows ----- , 3 , 17 What is the first term?

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Question 969971: Please help me solve this problem
the sequence is as follows
----- , 3 , 17
What is the first term?

Found 2 solutions by josgarithmetic, KMST:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Not enough given; term could be anything.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
We need more information than that.
Is there a commonly used pattern to your sequence?
Is 3 the second term, and 17 the third term?

A sequence could have no rhyme or reason, such as
potato , 3 , 7, duck , 1 , chair .
However, in algebra class teachers like sequences made with some sort of pattern.
The sequences with the commonly used patterns are an arithmetic sequence or a geometric sequence.

If it is an arithmetic sequence, then each term is the one before plus a fixed number, d .
That number d is called the common difference, because it is the difference between any two consecutive terms.
So, term number n%2B1 , a%5Bn%2B1%5D ,
is related to the previous term,
term number n=a%5Bn%5D,
by a%5Bn%2B1%5D=a%5Bn%5D%2Bd<--->d=a%5Bn%2B1%5D-a%5Bn%5D
for all natural number (counting number) values of n .
If 3 and 17 are the 2nd and 3rd terms respectively,
then the common difference between consecutive terms is
d-17-3=14 .
Each term is 14 more than the one before.
a%5B2%5D=3 , a%5B3%5D=17 , d=14 , and a%5B1%5D is the first term that we want to find.
From a%5Bn%2B1%5D=a%5Bn%5D%2Bd , for n=1 , we get
a%5B1%2B1%5D=a%5B1%5D%2Bd--->a%5B2%5D=a%5B1%5D%2B14--->3=a%5B1%5D%2B14
so a%5B1%5D%2B14=3--->a%5B1%5D=3-14--->a%5B1%5D=-11

If it is a geometric sequence, then each term is the one before times a fixed number, r .
That number r is called the common ratio, because it is the ratio between any two consecutive terms.
So, term number n%2B1 , b%5Bn%2B1%5D ,
is related to the previous term,
term number n=b%5Bn%5D,
by b%5Bn%2B1%5D=b%5Bn%5D%2Ar<--->r=b%5Bn%2B1%5D%2Fb%5Bn%5D
for all natural number (counting number) values of n .
If 3 and 17 are the 2nd and 3rd terms respectively,
then the common ratio between consecutive terms is
r=17%2F3 .
Each term is 17%2F3 times the one before.
b%5B2%5D=3 , b%5B3%5D=17 , r=17%2F3 , and b%5B1%5D is the first term that we want to find.
From b%5Bn%2B1%5D=b%5Bn%5D%2Ar , for n=1 , we get
b%5B1%2B1%5D=b%5B1%5D%2Ar--->b%5B2%5D=b%5B1%5D%2817%2F3%29--->3=b%5B1%5D%2817%2F3%29
so --->b%5B1%5D%2817%2F3%29=3--->b%5B1%5D=3%2F%28%2817%2F3%29%29--->b%5B1%5D=3%283%2F17%29--->b%5B1%5D=9%2F17