SOLUTION: Hello again, Can someone please help me with this problem? For the following system of non-linear equations sketch the graph, label the points of intersection of the two system

Algebra ->  Sequences-and-series -> SOLUTION: Hello again, Can someone please help me with this problem? For the following system of non-linear equations sketch the graph, label the points of intersection of the two system      Log On


   

Question 968002: Hello again,
Can someone please help me with this problem?
For the following system of non-linear equations sketch the graph, label the points of intersection of the two systems, and solve using substitution:
a) x^2 − y = 0
b) x + y = 2
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%5E2-y+=+0%2Cx+%2B+y+=+2%29

Solve the second equation for y:

x + y = 2
    y = 2 - x

Substitute (2 - x) for y in the first equation:

x%5E2+-+y+=+0
x%5E2+-+%282+-+x%29+=+0
x%5E2+-+2+%2B+x+=+0
x%5E2+%2B+x+-+2+=+0
%28x%2B2%29%28x-1%29+=+0
x%2B2=0,  x-1=0
x=-2,   x=1

Substitute x = -2 in

  y = 2 - x
  y = 2 - (-2)
  y = 2 + 2
  y = 4

So one point where they cross is (-2,4).

Substitute x = 1 in

  y = 2 - x
  y = 2 - (1)
  y = 2 - 1
  y = 1

So another point where they cross is (1,1).

Get some points on     x + y = 2, (-1,3), (-2,4), (0,2), (1,1), (2,0)
Get some points on     x^2 - y = 0, (-2,4), (-1,1), (0,0), (1,1), (2,4) 



Edwin