Question 956201: what comes after 3.5,13,41.5,127, , , ,
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website!
We try to find a multiplier, m, and an adder, a
3.5m+a = 13
13m+a = 41.5
41.5m+a = 127
Removing the decimals by multiplying each through by 2
7m+2a = 26
26m+2a = 83
83m+2a = 254
Solve the first for 2a
2a = 26-7m
Substitute in the second
26m+26-7m = 83
19m+26 = 83
19m = 57
m = 3
Substitute in
2a = 26-7m
2a = 26-7(3)
2a = 26-21
2a = 5
a = 2.5
See if those values satisfy
83m+2a = 254
83(3)+2(2.5) = 254
249 + 5 = 254
254 = 254
Yes they do!
So substituting in
3.5m+a = 13
13m+a = 41.5
41.5m+a = 127
3.5(3)+2.5 = 10.5+2.5 = 13
13(3)+2.5 = 39+2.5 = 41.5
41.5(3)+2.5 = 124.5+2.5 = 127
Continuing the pattern:
127(3)+2.5 = 381+2.5 = 383.5
383.5(3)+2.5 = 1150.5+2.5 = 1153
1153(3)+2.5 = 3459+2.5 = 3461.5
Edwin
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