SOLUTION: Find k,given that 32,k,3; are consecutive terms of an arithmetic sequence

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Question 953904: Find k,given that 32,k,3; are consecutive terms of an arithmetic sequence
Answer by MathLover1(20850) About Me  (Show Source):
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Since the terms are in arithmetic sequence,the middle term is equal to average of first and the last term.
so, for 32,k,3the middle term k=%2832%2B3%29%2F2=35%2F2 or as decimal k=17.5
or this way:
It's an arithmetic sequence so the difference between consecutive terms is constant.
the first difference is 32-k and the second difference is k-3, so we have
32-k+=k+-3
32%2B3+=2k+
35%2F2=k