SOLUTION: Hi would you please help me with this homework. Write a formula for the nth of the following geometric sequence. -3,3/4,-3/16,3/64... According to my professor the answer

Algebra ->  Sequences-and-series -> SOLUTION: Hi would you please help me with this homework. Write a formula for the nth of the following geometric sequence. -3,3/4,-3/16,3/64... According to my professor the answer      Log On


   



Question 930752: Hi would you please help me with this homework.
Write a formula for the nth of the following geometric sequence.
-3,3/4,-3/16,3/64...
According to my professor the answer is an=-3*(-1/4)^n-1
Would you please show me the steps on how to solve this problem. Thank you

Found 3 solutions by jim_thompson5910, josgarithmetic, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The first term is -3. So a = -3

The common ratio is -1/4. This is because you multiply each term by -1/4 to get the next term.

You can see this if you divide the second term (3/4) by the first term (-3) and you'll get -1/4. You could also divide the third term by the 2nd term, or the 4th over the 3rd, etc etc

So r = -1/4

-------------------------------------------------------

We now know

a = -3
r = -1/4

You plug them into the general geometric sequence formula

an = a*(r)^(n-1)

to get

an = -3*(-1/4)^(n-1)

------------------------------------------------------------------------------------------------------------------------

If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).

Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.

Jim
------------------------------------------------------------------------------------------------------------------------

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
You should check each successive pair of terms for a common ratio. You will find it to be -1%2F4, forming the same general term expected.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

-3,3%2F4,-3%2F16,3%2F64...=>you are given a geometric sequence
so, the first term a%5B1%5D and the common ratio r, the nth (or general) term is given by:
a%5Bn%5D+=+a%5B1%5D%2Ar%5E%28n-1%29

use two terms to find the common ratio r:
1st a%5B1%5D=-3
r=a%5B2%5D%2Fa%5B1%5D=%283%2F4%29%2F-3=-3%2F12=-1%2F4
check the formula:
a%5B1%5D+=+a%5B1%5D%2Ar%5E%28n-1%29 if n=1
a%5B1%5D+=+-3%2A%28-1%2F4%29%5E%281-1%29
a%5B1%5D+=+-3%2A%28-1%2F4%29%5E0........%28-1%2F4%29%5E0=1
a%5B1%5D+=+-3%2A1
a%5B1%5D+=+-3

a%5B2%5D+=+a%5B1%5D%2Ar%5E%28n-1%29 if n=2
a%5B2%5D+=+-3%2A%28-1%2F4%29%5E%282-1%29
a%5B2%5D+=+-3%2A%28-1%2F4%29%5E1........%28-1%2F4%29%5E0=1
a%5B2%5D+=+-3%2A%28-1%2F4%29
a%5B2%5D+=+-3%2F-4
a%5B2%5D+=+3%2F4
this way you can find the terms coming after