Question 912209: write the first 5 terms in this sequence f(n)=5(1/2)^n
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! f(n)=5(1/2)^n
f(0)=5(1/2)^(0) ... plug in n = 0
f(0)=5(0.5)^(0)
f(0)=5(1)
f(0)=5
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f(n)=5(1/2)^n
f(1)=5(1/2)^(1) ... plug in n = 1
f(1)=5(0.5)^(1)
f(1)=5(0.5)
f(1)=2.5
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f(n)=5(1/2)^n
f(2)=5(1/2)^(2) ... plug in n = 2
f(2)=5(0.5)^(2)
f(2)=5(0.25)
f(2)=1.25
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f(n)=5(1/2)^n
f(3)=5(1/2)^(3) ... plug in n = 3
f(3)=5(0.5)^(3)
f(3)=5(0.125)
f(3)=0.625
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f(n)=5(1/2)^n
f(4)=5(1/2)^(4) ... plug in n = 4
f(4)=5(0.5)^(4)
f(4)=5(0.0625)
f(4)=0.3125
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The first five terms are: 5, 2.5, 1.25, 0.625, 0.3125
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