SOLUTION: sn problem; above greek symbol is k on the bottom is n=0. Directly next to it is n^2=(k(k+1)(2k+1))/6 check that its correct for k=1,2, and 3. B.) Use the same formula to comput

Algebra ->  Sequences-and-series -> SOLUTION: sn problem; above greek symbol is k on the bottom is n=0. Directly next to it is n^2=(k(k+1)(2k+1))/6 check that its correct for k=1,2, and 3. B.) Use the same formula to comput      Log On


   

Question 892532: sn problem; above greek symbol is k on the bottom is n=0. Directly next to it is n^2=(k(k+1)(2k+1))/6 check that its correct for k=1,2, and 3.
B.) Use the same formula to compute the value of m=0 top 5 (2m^3+3m-4)
Thank you.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
That's the Greek letter sigma, btw. For example:



If k = 3, then which is a true statement.

Basically, just replace the index (in the above case, n) with its starting value and increment until you get to the top number, and add everything up.