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Question 88818:
Answer by malakumar_kos@yahoo.com(315) About Me  (Show Source):
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find the value of a[n] if: n=2, a[1] and a[n]=3a[n-1]+1
a(n) = 3a(n-1)+1
a(1) = 3a(1-1)+1 = 3a*0+1 = 0+1 = 1
a(2) = 3a(2-1)+1 = 3a(1)+1 = 3a+1