SOLUTION: A recursive formula for the following series: 1, 3/2, 5/6, 7/24, 9/120

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Question 871381: A recursive formula for the following series: 1, 3/2, 5/6, 7/24, 9/120
Found 2 solutions by KMST, richwmiller:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
A recursive formula shows how to get the next term from the one before, to X%5Bn%5D from X%5Bn-1%5D .
I know the idea to get x%5Bn%5D from X%5Bn-1%5D .
From the terms you are given, in the form given,
to get term number n ,
you add 2 to the numerator and multiply the denominator by n .
So for the 6th term, you take 9%2F120 ;
change the numerator from 9 to 9%2B2=11 ,
and change the denominator from 120 to 120%2A6=720,
to get 11%2F720.

However, if I was given 3%2F40 as a term, how would I know that 3%2F40=9%2F120 ,
and how would I know that 3%2F40=9%2F120 is the fifth term.
It is not so easy.
I could do it, but I do not know how to write it as a recursive formula..

I do see an explicit formula to calculate term number n from n , not counting on term number n-1 ) .
X%5Bn%5D=%282n-1%29%2Fn%21
X%5B1%5D=%282%2A1-1%29%2F1%21=%282-1%29%2F1=1%2F1=1
X%5B2%5D=%282%2A2-1%29%2F2%21=%284-1%29%2F%281%2A2%29=3%2F2
X%5B3%5D=%282%2A3-1%29%2F3%21=%286-1%29%2F%281%2A2%2A3%29=5%2F6
X%5B4%5D=%282%2A4-1%29%2F4%21=%288-1%29%2F%281%2A2%2A3%2A4%29=7%2F24
X%5B5%5D=%282%2A5-1%29%2F5%21=%2810-1%29%2F%281%2A2%2A3%2A4%2A5%29=9%2F120

If you only told me that one of the terms is 3%2F40 ,
I would factor 40 as 40=2%2A2%2A2%2A5=2%2A4%2A5 .
I would multiply numerator and denominator times 3 ,
to have 2%2A3%2A4%2A5=5%21 as a denominator.
Then, suspecting that 3%2F40=3%2A3%2F%2840%2A3%29=9%2F120 is term number n=5 ,
I would verify that with n%21=5%21 as denominator, the numerator is 2n-1=2%2A5-1=10-1=9.
After that, from 9%2F120 ,
I would change the numerator from 9 to 9%2B2=11 ,
and change the denominator from 120 to 120%2A6=720,
to get 11%2F720.
I cannot write that as a recursive formula,
but since no one else answered your question before,
I assume that not many people can.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
(n+2)/d!*(d+1))
where n is last numerator
and d! is last denominator