,
If the sequence is arithmetic, we use the formula:
three times. Once for n=3. once for n=8, and once using
the values for t1 and d.
--------------------------
Substitute n = 3
Substitute 15 for t3
-------------------------
Substitute n = 8
Substitute 50 for t8
So you have this system of equations to solve:
Solve that system by substitution or elimination and
get
and
---------------------------------
Therefore
becomes
Edwin