SOLUTION: Is this correct?
Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8, to find the following:
What is r, the ratio between 2 consecutive terms?
Answer: r = (1/2)/1 = 1/2
Algebra ->
Sequences-and-series
-> SOLUTION: Is this correct?
Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8, to find the following:
What is r, the ratio between 2 consecutive terms?
Answer: r = (1/2)/1 = 1/2
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Question 83996: Is this correct?
Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8, to find the following:
What is r, the ratio between 2 consecutive terms?
Answer: r = (1/2)/1 = 1/2
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Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Please round your answer to 4 decimals.
Answer:
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S(n) = a(1)[r ^(n + 1) 1)/(r 1)
S(10) = 1[(1/2) ^ 9 1] / [(1/2)-1]
S(10) = [-0.998046875 ] / [-0.5] = 1.99609375
Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Please round your answer to 4 decimals.
Answer:
Show work in this space.
S(n) = a(1)[r ^(n + 1) 1)/(r 1)
S(12) = 1[(1/2) ^ 9 1] / [(1/2)-1]
S(12) = [-0.998046875 ] / [-0.5] = 1.99609375
n = 12
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The ratio r is the factor to get from term to term. So
r=nth term/(n-1) term
The sequence is cut in half each term, so the sequence is
The sum of a geometric series is where a=1 So plug in n=10 to find the sum of the first 10 partial sums
So the sum of the first ten terms is or 1.99805 approximately
Use the same formula to find the sum of the 1st 12 terms where a=1 So plug in n=12 to find the sum of the first 12 partial sums
So the sum of the first twelve terms is or 1.99951 approximately