SOLUTION: find the missing term of number series 3,10,20,33,49,68, ?

Algebra ->  Sequences-and-series -> SOLUTION: find the missing term of number series 3,10,20,33,49,68, ?      Log On


   



Question 834464: find the missing term of number series 3,10,20,33,49,68, ?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The differences between consecutive terms are 7, 10, 13, 16, 19:
10-3=7
20-10=10
33-20=13
49-33=16
69-49=19 .
Each difference is 3 more than the one before.
The next difference would be 19%2B3=22 ,
so the next term would be 68%2B22=highlight%2890%29 .