Question 833287: Let Pn denote the population size of ring-necked pheasants on Protection
Island on 1 April, n years after 1937; thus P0 represents the population
size on 1 April 1937, which is 8. Assume that the number of births in each
subsequent year (from 1 April to 31 March) is 2.6Pn (that is, 260% of Pn),
and the number of deaths in each subsequent year is 0.4Pn (40% of Pn).
During the (n+ 1)th year, the ‘joiners’ will be the pheasants born
during the year, of which there are 2.6Pn, and the ‘leavers’ will be the
pheasants that die, of which there are 0.4Pn. The difference between
births and deaths gives the increase in the population size during the
year (since we are assuming that there is no migration), so
Pn+1 − Pn = 2.6Pn − 0.4Pn
= 2.2Pn.
Thus the sequence Pn is given by
P0 = 8, Pn+1 = 3.2Pn (n = 0,1,2,...).
[I NEED TO UNDERSTAND WHERE 3.2 APPEARS FROM]
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Input the equation of the given line in slope-intercept form. The line through (1,0) and parallel to x - y = 7.
-----
3.2 is probably a typo. It should be 2.2
=====================
Cheers,
Stan H.
=============
|
|
|
