You can put this solution on YOUR website! write the binomial expression in simplified form of (2j-k^2)^3
The formula for this is:
(a+b)^n=a^n+C(1,n)a^(n-1)b+C(2,n)a^(n-2)b^2+...+C(n-1,n)ab^(n-1)+b^n
In your case a=2j, b=-k^2, n=3,
C(1,3)=3, C(2,3)=3 (This part can be found using Pascal's Triangle as well.)
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Happy Calculating!!!!