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let a number be and another number
number times another number equals :
........eq.1
and the sum of :
........eq.2
solve the system:
........eq.1 ........eq.2
__________________________
........eq.2.....solve for ........eq.2a.....substitute in eq.1
........eq.1...solve for ......use quadratic formula
solutions:
now find ........eq.2a
or
so, one solution is and
and another is vs, and
check: ........eq.1=>...rounded ........eq.2=>