SOLUTION: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40
Algebra ->
Sequences-and-series
-> SOLUTION: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40
Log On
Question 790518: Given the sequence of first differences: 8, 10, 12, 14 find the first six terms of the original sequence if the sum of the third and fourth terms of the original sequence is 40 Answer by solver91311(24713) (Show Source):
The difference between and is 12 from the sequence of first differences, and the sum of and is given as 40. That is a 2X2 system. Solve the 2X2 system for and , then the rest should just fall into place.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
