SOLUTION: 12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ... In the sequence above, the first term is 12^10 more than the preceding term. Which term in the sequence is equal to 12^12?

Algebra ->  Sequences-and-series -> SOLUTION: 12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ... In the sequence above, the first term is 12^10 more than the preceding term. Which term in the sequence is equal to 12^12?       Log On


   

Question 788113: 12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ...
In the sequence above, the first term is 12^10 more than the preceding term. Which term in the sequence is equal to 12^12?
A. The 3rd term
B. The 12th term
C. The 24th term
D. The 120th term
E. The 144th term
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
In that sequence, the first term is 12%5E10, and each term is 12%5E10 more than the preceding term.
a%5B1%5D=12%5E10= first term
d=12%5E10= common difference
a%5Bn%5D=a%5B1%5D%2B%28n-1%29d= nth term
12%5E12=12%5E10%2B%28n-1%2912%5E10
12%5E12=12%5E10%281%2B%28n-1%29%29
12%5E12=12%5E10%2An
12%5E12%2F12%5E10=n
12%5E%2812-10%29=n
12%5E2=n --> highlight%28n=144%29