z(5)=9,z(6)=12,z(7)=15,z(8)=18. If z = lny,
find a formula for y in terms of x.
9, 12, 15, 18 forms an arithmetic sequence
with common difference = d = 3. So we make
lists of x, 3x, z(x) and 3x-z(x)
x 3x z(x) 3x-z(x)
5 15 9 6
6 18 12 6
7 21 15 6
8 24 18 6
We see that 3x - z(x) = 6 in every case, so
3x - z(x) = 6
-z(x) = -3x + 6
z(x) = 3x - 6
Since z(x) = ln(y), y = ez(x) = e3x-6
or if you prefer, y = e3(x-2)
Edwin