SOLUTION: Find the Infinite G.P. whose second term is 2/9 and sum to infinity is unity.

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Question 765625: Find the Infinite G.P. whose second term is 2/9 and sum to infinity is unity.
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
For a GP whose 1st term is a and common ratio is r,
Sum to infinity = a%2F%281-r%29   ---> Assumption is r < 1

Here, since sum to infinity = 1,
a%2F%281-r%29+=+1  or a+=+1+-r

Second term = a*r = %281++-+r%29%2Ar+=+r+-+r%5E2+=+2%2F9

Simplifying

9%2Ar+-+9%2Ar%5E2+=+2

9%2Ar%5E2+-+9%2Ar+%2B+2+=+0

Solving using the quadratic solver (see below), we get the 2 solutions as
r = 1/3 or r = 2/3

Correspondingly, a = 1 - r = 2/3 or 1/3

So there are 2 possible GP's:

1) a = 1/3, r = 2/3 i.e. 1/3,2/9,4/27 etc.
2) a = 2/3, r = 1/3 i.e. 2/3,2/9,2/27 etc.

In both cases, the second term is 2/9 and the sum to infinity is 1.

Hope you got it:)

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 9x%5E2%2B-9x%2B2+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-9%29%5E2-4%2A9%2A2=9.

Discriminant d=9 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--9%2B-sqrt%28+9+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-9%29%2Bsqrt%28+9+%29%29%2F2%5C9+=+0.666666666666667
x%5B2%5D+=+%28-%28-9%29-sqrt%28+9+%29%29%2F2%5C9+=+0.333333333333333

Quadratic expression 9x%5E2%2B-9x%2B2 can be factored:
9x%5E2%2B-9x%2B2+=+9%28x-0.666666666666667%29%2A%28x-0.333333333333333%29
Again, the answer is: 0.666666666666667, 0.333333333333333. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+9%2Ax%5E2%2B-9%2Ax%2B2+%29