SOLUTION: 7 ∑ 2k/3 k-1 Hard to type this question. The 7 is above and the k=1 below the sigma

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Question 738572: 7
∑ 2k/3
k-1
Hard to type this question. The 7 is above and the k=1 below the sigma
Answer by MathLover1(20850) About Me  (Show Source):