SOLUTION: The tickets in a raffle are numbered 1, 2, 3, and so on. The price of a ticket is the number of cents equal to the number of the ticket. If the raffled article cost $100, what is t

Algebra ->  Sequences-and-series -> SOLUTION: The tickets in a raffle are numbered 1, 2, 3, and so on. The price of a ticket is the number of cents equal to the number of the ticket. If the raffled article cost $100, what is t      Log On


   

Question 732158: The tickets in a raffle are numbered 1, 2, 3, and so on. The price of a ticket is the number of cents equal to the number of the ticket. If the raffled article cost $100, what is the least number of tickets that must be sold so that those conducting the raffle will not lose money?
Found 2 solutions by mananth, xtian:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
It is an AP
a=1
d=1
Sn=$100= 10000 cents
Sn=n/2[2a+(n-1)d]
10000=n/2[2+n-1]
20000=n^2+n
n^2+n-20000=0
Find the roots of the equation by quadratic formula

a= 1 , b= 1 , c= -20000

b^2-4ac= 1 + 80000
b^2-4ac= 80001
%09sqrt%28%0980001%09%29=%09282.84%09
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -1 + 282.84 )/ 2
x1= 140.92
x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x2=( -1 -282.84 ) / 2
x2= -141.92
Ignore negative value Minimum tickets to be sold = 141 tickets

m.ananth@hotmail.ca

Answer by xtian(1) About Me  (Show Source):
You can put this solution on YOUR website!
we'll again. thank you very much. :) can you teach me how to improve my skills in solving math problems. because i see that i have poor skills in solving math problems. especially when it comes to worded problems. :(