1st term = x+1,
2nd term = 3x-2,
and
3rd term = 4x+5
In order to form an arithmetic sequence, this must be true:






(3x-2)-(x+1) = (4x+5)-(3x-2)
You solve that and get x=10.
So
1st term = x+1 = 10+1 = 11
2nd term = 3x-2 = 3(10)-2 = 30-2 = 28
and
3rd term = 4x+5 = 4(10)+5 = 40+5 = 45
So the series is 11, 28, and 45.
Checking in






28 - 11 = 45 - 28
17 = 17.
So the answer is correct with a common difference of d=17.
Edwin