SOLUTION: Determine the number of terms in the following arithmetic sequence: 315, 304, 293, ... , 18.

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Question 711986: Determine the number of terms in the following arithmetic sequence: 315, 304, 293, ... , 18.
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the number of terms in the following arithmetic sequence:
315, 304, 293, ... , 18
-----
a = 315
d = 304-315 = -11
----
Solve for "n":
a(n) = a + (n-1)d
----
18 = 315 + (n-1)(-11)
-297 = (n-1)(-11)
n-1 = (-297/-11)
n-1 = 27
n = 28 (# of terms)
=====================
Cheers,
Stan H.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

as you can see, in the following arithmetic sequence, 315, 304, 293, ... , 18, the difference between each term is -11 (the fixed amount is called the common difference, d=a%5B2%5D-a%5B1%5D=304-3115=-11)
315
315-11=304
304-11=293...then next term will be
293-11=282
282-11=271....and so on, up to 18

To find any term of an arithmetic sequence use formula:
a%5Bn%5D=a%5B1%5D%2B%28n-1%29d where a%5B1%5D is the first term of the sequence,
d is the common difference, n is the number of the term to find
in your case is given a%5B1%5D=315,a%5Bn%5D=18, and we found that d=-11
a%5Bn%5D=a%5B1%5D%2B%28n-1%29d...solve for n
a%5Bn%5D-a%5B1%5D=%28n-1%29d
%28a%5Bn%5D-a%5B1%5D%29%2Fd=n-1
%28a%5Bn%5D-a%5B1%5D%29%2Fd%2B1=n......plug in given values
%2818-315%29%2F-11%2B1=n
%2818-315%29%2F-11%2B1=n
-297%2F-11%2B1=n
27%2B1=n
28=n......the number of terms