SOLUTION: I can't figure this out. Please help. Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer

Algebra ->  Sequences-and-series -> SOLUTION: I can't figure this out. Please help. Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer      Log On


   



Question 68833: I can't figure this out. Please help.
Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following:
a) What is r, the ratio between 2 consecutive terms?
Answer:
Show work in this space.



b) Using the formula for the nth term of a geometric sequence, what is the 10th term?
Answer:
Show work in this space.



c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms?
Answer:
Show work in this space.

Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!
Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following:
a) What is r, the ratio between 2 consecutive terms?
Answer:
Definition:
A sequence is geometric if there exist a number r, called the common ratio, such that multiplying the previous term by r results in the next term.

%28%28a%5Bk%2B1%5D%29%2Fa%5Bk%5D%29+=+r
%28%28a%5Bk%2B1%5D%29%2Fa%5Bk%5D%29+=+%283%2F1%29=+r%29
r+=+3%2F1
highlight+%28r+=+3%29



b) Using the formula for the nth term of a geometric sequence, what is the 10th term?
Answer:
The nthe term of a geometric sequence is given by:


%28a%5Bn%5D%29+=+%28a%5B1%5Dr%5E%28n-1%29%29, r ≠ 0

n = 10 ---> 10th term
a[1] = 1 ---> first term
r = 3 ---> common ratio


a%5B10%5D+=+1%2A3%5E%2810-1%29
a%5B10%5D+=+1%2A3%5E9
a%5B10%5D+=+3%5E9
a%5B10%5D+=+19+683



c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms?
Answer:
The partial sum of the first n terms of a geometric sequence is given by:
S%5Bn%5D+=+%28%28a%5B1%5D%2Ar%5En-1%29%2F%28r+-+1%29%29 , r≠1
Where, S%5Bn%5D = Partial sum
a%5B1%5D=+1 --->> first term
r = 3 -----> common ratio
n = 10 ----> 10th term


S%5Bn%5D+=+%28%281%2A3%5E10-1%29%2F%283+-+1%29%29
S%5Bn%5D+=+%28%2859049-1%29%2F2%29
S%5Bn%5D+=+29+524.5