SOLUTION: Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n &#8805; 2 list the first terms of the sequence?

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Question 631899: Suppose that a sequence is defined as follows.
a[1] = -1 , a[n] = -3a[n-1]+6 for n ≥ 2
list the first terms of the sequence?
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi,
a[1] = -1 , a[n] = -3a[n-1]+6 for n ≥ 2 Note:
a[2] = 3[2-1]+6
a[3] = 3[3-1]+6
a[4] = 3[4-1]+6
Complete the Arithemetic

Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

Substitute 2 for and do the arithmetic to get the 2nd term. Substitute 3 for and do the arithmetic to get the 3rd term. Repeat as often as necessary to get the number of terms you want.

John

My calculator said it, I believe it, that settles it

SOLUTION: Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n &#8805; 2 list the first terms of the sequence?

SOLUTION: Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n ≥ 2 list the first terms of the sequence?