SOLUTION: I have a problem that I simply cannot solve. I have to put this series into summation notation, but I can't find the explicit formula! The series is 1 + 1/4 + 1/9 + 1/16 + 1/25

Algebra ->  Sequences-and-series -> SOLUTION: I have a problem that I simply cannot solve. I have to put this series into summation notation, but I can't find the explicit formula! The series is 1 + 1/4 + 1/9 + 1/16 + 1/25       Log On


   



Question 608591: I have a problem that I simply cannot solve. I have to put this series into summation notation, but I can't find the explicit formula! The series is
1 + 1/4 + 1/9 + 1/16 + 1/25
How do I even find the common difference in a series like that?

Found 2 solutions by ewatrrr, Edwin McCravy:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
Series: a%5Bn%5D+=+1%2Fn%5E2
1 + 1/4 + 1/9 + 1/16 + 1/25 = sum%28+1%2Fn%5E2%2C+n=1%2C+5+%29

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
I have a problem that I simply cannot solve. I have to put this series into summation notation, but I can't find the explicit formula! The series is
1 + 1/4 + 1/9 + 1/16 + 1/25
How do I even find the common difference in a series like that?
That is neither an arithmetic nor a geometric series.  You are not asked
to find the sum of the series.  You are only asked to find the summation
series.  What you want is this:

Re-write the series 

1 + 1%2F4 + 1%2F9 + 1%2F16 + 1%2F25 

as this:

1%2F1%5E2 + 1%2F2%5E2 + 1%2F3%5E2 + 1%2F4%5E2 + 1%2F5%5E2

That can be written this way:

sum%281%2Fk%5E2%2Ck=1%2C5%29

k is the "dummy" variable, sometimes called the "index".
You can use another letter besides k if you like.  The ∑
is the Greek letter "sigma" for "S" which stands for "SUM" 
At the bottom of the ∑ is k=1 and the top is 5.  At the
right of the ∑ you see a formula 1%2Fk%5E2.  This means
to start out by substituting 1 for k in the formula 1%2Fk%5E2
getting 1%2F1%5E2 which is 1.  You write that down as the first
term.

So you have 1

Then you substitute k=2 in that formula 1%2Fk%5E2
getting 1%2F2%5E2 which is 1%2F4, so you put a + after the
1 and write that after it:

Now you have 1 + 1%2F4

Then you substitute k=3 in that formula 1%2Fk%5E2
getting 1%2F3%5E2 which is 1%2F9, so you put a + and write 
that after it:

Now you have 1 + 1%2F4 + 1%2F9

Then you substitute k=4 in that formula 1%2Fk%5E2
getting 1%2F4%5E2 which is 1%2F16, so you put a + and write 
that after it:

Now you have 1 + 1%2F4 + 1%2F9 + 1%2F16

Then you substitute k=5 in that formula 1%2Fk%5E2
getting 1%2F5%5E2 which is 1%2F25, so you put a + and write 
that after it:

Now you have 1 + 1%2F4 + 1%2F9 + 1%2F25

And you have finished because there is a 5 at the top of the ∑
which tells you when to stop.

But all you were asked to give as an answer is

sum%281%2Fk%5E2%2Ck=1%2C5%29

Edwin