SOLUTION: 1+3+5+7+ . . . +99+101 = (?) Please show me the steps.

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Question 574501: 1+3+5+7+ . . . +99+101 = (?) Please show me the steps.
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
1 = 1 = 1%5E2
1+3 = 4 = 2%5E2
1+3+5 = 9 = 3%5E2
1+3+5+7 = 16 = 4%5E2
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The sum of the first n odd numbers is n%5E2.
The nth odd number is 2n-1.
2n-1 = 101
n = 51
There are 51 odd numbers from 1 to 101, inclusive.
The sum of the first 51 odd numbers is 51%5E2=2601
Answer: 2601