SOLUTION: here's the sequence: 1, 1/4, 1/9 ,1/16 or 1, .25, 1.111111repeating, .0625 What is the pattern?? and if you figure out the pattern, i'll find out on my own the next two numbers.

Algebra ->  Sequences-and-series -> SOLUTION: here's the sequence: 1, 1/4, 1/9 ,1/16 or 1, .25, 1.111111repeating, .0625 What is the pattern?? and if you figure out the pattern, i'll find out on my own the next two numbers.       Log On


   



Question 57164This question is from textbook
: here's the sequence:
1, 1/4, 1/9 ,1/16 or 1, .25, 1.111111repeating, .0625
What is the pattern?? and if you figure out the pattern, i'll find out on my own the next two numbers.
This question is from textbook

Found 3 solutions by funmath, checkley71, rcmcc:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
1,1%2F4, 1%2F9 ,1%2F16
1=1%2F1%5E2,1%2F4=1%2F2%5E2, 1%2F9=1%2F3%5E2, 1%2F16=1%2F4%5E2
The pattern is:1%2Fn%5E2
Happy Calculating!!!

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
1/1^2 1/2^2 1/3^2 1/4^2 1/5^2
1 1/4 1/9 1/16 1/25
1/1^2 1/2^2 1/3^2 1/4^2 1/5^2
1/1=1 1/4=.25 1/9=1/.1111111 1/25=1/.0625 YOU HAVE A MISTAKE(?) WITH THE 1/1.11111 & 1/25=.04

Answer by rcmcc(152) About Me  (Show Source):
You can put this solution on YOUR website!
The pattern of your sequence is an expanded geometric sequence. It is calculated by taking the inverse of the square of the term. Or by the formula below.

T= 1/(tn^2)
so, your sequence is:
1=1/(1^2)
(1/4)=1/(2^2)
(1/9)=1/(3^2)
(1/16)=1/(4^2)
and the next 2 numbers can be solved by

T5=1/(5^2)
T5=1/25
T6=1/(6^2)
T6=1/36