SOLUTION: i need to find the nth term of a pattern with consecutive even numbers, ive tried many solutions but neither see to be working. please help.

Algebra ->  Sequences-and-series -> SOLUTION: i need to find the nth term of a pattern with consecutive even numbers, ive tried many solutions but neither see to be working. please help.      Log On


   

Question 554879: i need to find the nth term of a pattern with consecutive even numbers, ive tried many solutions but neither see to be working. please help.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If you have consecutive even numbers, each one is equal to the previous one plus 2.
That could be written as a%5Bn%5D=a%5Bn-1%5D+%2B2 or a%5Bn%2B1%5D=a%5Bn%5D+%2B2 .
If your first term is a%5B1%5D, the second would be a%5B2%5D=a%5B1%5D%2B2 .
The third one would be a%5B3%5D=a%5B2%5D%2B2%2Ba%5B2%5D=a%5B1%5D%2B2%2B2
The fourth one would be a%5B4%5D=a%5B1%5D%2B2%2B2%2B2
The fifth one would be a%5B5%5D=a%5B1%5D%2B2%2B2%2B2%2B2, and so on.
Each time you calculate the next term, you are adding 2.
When you get to the nth term, you have added n-1 times the number 2, so
a%5Bn%5D=a%5B1%5D%2B2%28n-1%29