SOLUTION: prove that if k>1 then k^n→∞ an n→∞
there is a hint given. Hint:let k=1+t where t>0 and use the fact that (1+t)^n>1+nt
prove that if k is between 0 an
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-> SOLUTION: prove that if k>1 then k^n→∞ an n→∞
there is a hint given. Hint:let k=1+t where t>0 and use the fact that (1+t)^n>1+nt
prove that if k is between 0 an
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Question 550089: prove that if k>1 then k^n→∞ an n→∞
there is a hint given. Hint:let k=1+t where t>0 and use the fact that (1+t)^n>1+nt
prove that if k is between 0 and 1 then k^n tends to 0 as n tends to infinity Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! Given the hint, the problem becomes simple. Since 1 + nt approaches infinity as n approaches infinity, the LHS of the inequality is "bounded" by this expression, so the LHS must also approach infinity.
