SOLUTION: I'm not too sure how to write this, but the problem is ... a four is over the sign for sigma and under it is m=1 then (2/m - 2/m+1) I am to write this sum without using sigma nota

Algebra ->  Sequences-and-series -> SOLUTION: I'm not too sure how to write this, but the problem is ... a four is over the sign for sigma and under it is m=1 then (2/m - 2/m+1) I am to write this sum without using sigma nota      Log On


   

Question 48303This question is from textbook College Algebra
: I'm not too sure how to write this, but the problem is ... a four is over the sign for sigma and under it is m=1 then (2/m - 2/m+1) I am to write this sum without using sigma notation; then compute the sum. Please help if you can. Thank you! This question is from textbook College Algebra

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Highest Value = 4
Minimum Value = 1
(2/1 - 2/(1 + 1)) + (2/2 - 2/(2 + 1)) + (2/3 - 2/(3 + 1)) + (2/4 - 2/(4 + 1))
(2 - 1) + (1 - 2/3) + (2/3 - 1/2) + (1/2 - 2/5)
(1) + (3/3 - 2/3) + (4/6 - 3/6) + (5/10 - 4/10)
(1) + (1/3) + (1/6) + (1/10)
30/30 + 10/30 + 5/30 + 3/30
48/30 or 1 3/5