You can put this solution on YOUR website! the second term of a geometric sequence is 10 and the fifth term is 7290. find the nth term
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Form: a(n) = ab^(n-1)
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a(5) = ab^4 = 7290
a(2) = ab = 10
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Divide a(5) by a(2) to solve for "b":
b^3 = 729
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b = 9
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Solve for "a":
ab = 10
a*9 = 10
a = 10/9 = 1.11111..
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nth term = (10/9)(9)^n
a(n) = 10*9^(n-1)
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Cheers,
Stan H.
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