SOLUTION: 1) Find the fraction form of 8.25 recurring Please help
I keep getting 817/99 but upon checking its not quite right
2) Find the first four terms of the expansion(x-3)^6, this h
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-> SOLUTION: 1) Find the fraction form of 8.25 recurring Please help
I keep getting 817/99 but upon checking its not quite right
2) Find the first four terms of the expansion(x-3)^6, this h
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Question 434561: 1) Find the fraction form of 8.25 recurring Please help
I keep getting 817/99 but upon checking its not quite right
2) Find the first four terms of the expansion(x-3)^6, this has me stumped Please help, thank you in advance Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1) Find the fraction form of 8.25 recurring Please help
--
::::100x = 825.252525...
when x = 8.252525....
----
Subtracting you get 99x = 817
and x = 817/99
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2) Find the first four terms of the expansion(x-3)^6,
----
6C6*x^6*(-3)^0
+ 6C5*x^5*(-3)^1
+ 6C4*x^4*(-3)^2
+ 6C3*x^3*(-3)^3
....
Simplify:
x^6 + 6*-3*x^5 + 15*9*x^4 + 30*(-27)x^3...
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Final Form:
x^6 -18x^5 +135x^4 -810x^3....
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Cheers,
Stan H.
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