SOLUTION: a four person committee is to be elected from an organization's membership of 11 people. how many different committees are possible I know it is 11c4, but what is the value of

Algebra ->  Sequences-and-series -> SOLUTION: a four person committee is to be elected from an organization's membership of 11 people. how many different committees are possible I know it is 11c4, but what is the value of       Log On


   

Question 412153: a four person committee is to be elected from an organization's membership of 11 people. how many different committees are possible
I know it is 11c4, but what is the value of this?
Thanks
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that n C r = (n!)/(r!(n-r)!)


In this case, n=11 and r=4


So we get


11 C 4 = (11!)/(4!(11-4)!) = (11!)/(4!7!) = (11*10*9*8*7!)/(4!7!) = (11*10*9*8)/(4*3*2*1) = 7920/24 = 330


So 11 C 4 = 330, which means that there are 330 different committee.


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