SOLUTION: Please help me, Im having so much trouble with this question. Use Pascals triangle to expand (x-7)^5

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Question 394655: Please help me, Im having so much trouble with this question.
Use Pascals triangle to expand (x-7)^5

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Pascal's triangle is very useful for finding the
coefficients of any expression of the form
%28a+%2B+b%29%5Ek , where k+=+1%2C2%2C3%2C+.+.+. etc.
Each entry is the sum of the entries on the
previous line on the left and right.
the triangle looks like:
1 - - - - - 1
1 - - 2- - 1
1 - 3 - -3 -1
1 4 - 6 - 4 1
It's hard to show on the computer, but
the next line is the one you need:
1 - 5 - 10 - 10 - 5 - 1
These are the coefficients of the
expansion of %28a+%2B+b%29%5E5
It tells you there are 6 terms in
the expansion.
The first term is a%5E5, and the coefficient is 1
The last term is b%5E5, and the coefficient is also 1
The whole expansion looks like
a%5E5+%2B+5a%5E4b+%2B+10a%5E3b%5E2+%2B+10a%5E2b%5E3+%2B+5a%2Ab%5E4+%2B+b%5E5
You may wonder what this does for you.
Well, I you just say
a+=+x and
b+=+-7, your problem is solved

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Here's a list of the nasty powers of -7:
%28-7%29%5E2+=+49
%28-7%29%5E3+=+-343
%28-7%29%5E4+=+2401
%28-7%29%5E5+=+-16807
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x%5E5+-+35x%5E4+%2B+490x%5E3+-+3430x%5E2+%2B+12005x+-+16807 answer
Hope this helps